Șepreuș
Commune in Arad, Romania / From Wikipedia, the free encyclopedia
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Șepreuș (Hungarian: Seprős) is a commune in Arad County, Romania, is situated on the northern part of the Teuz Plateau, it stretches over 5768 ha. It is composed of a single village, Șepreuș, situated at 63 km from Arad.
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Quick Facts Country, County ...
Șepreuș | |
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Coordinates: 46°34′N 21°44′E | |
Country | Romania |
County | Arad |
Population (2021-12-01)[1] | 2,752 |
Time zone | EET/EEST (UTC+2/+3) |
Vehicle reg. | AR |
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