1948 U.S. National Championships – Women's singles
1948 tennis event results / From Wikipedia, the free encyclopedia
Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the women's singles tennis title at the 1948 U.S. National Championships.[1][2]
Quick Facts Women's singles, Final ...
Women's singles | |||||||
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1948 U.S. National Championships | |||||||
Final | |||||||
Champion | Margaret Osborne duPont[1] | ||||||
Runner-up | Louise Brough | ||||||
Score | 4–6, 6–4, 15–13 | ||||||
Events | |||||||
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