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1936 U.S. National Championships – Women's singles

1936 tennis event results From Wikipedia, the free encyclopedia

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Third-seeded Alice Marble defeated first-seeded Helen Jacobs 4–6, 6–3, 6–2 in the final to win the women's singles tennis title at the 1936 U.S. National Championships. The tournament was played on outdoor grass courts and held from September 3, through September 12, 1936 at the West Side Tennis Club in Forest Hills, Queens, New York.[1][2][3]

Quick facts Women's singles, Final ...

The draw consisted of 64 players of which eight were seeded.

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Seeds

The eight seeded U.S. players are listed below. Alice Marble is the champion; others show in brackets the round in which they were eliminated.[4]

  1. United States Helen Jacobs (finalist)
  2. United States Sarah Fabyan (first round)
  3. United States Alice Marble (champion)
  4. United States Carolin Babcock (quarterfinals)
  5. United States Marjorie Van Ryn (third round)
  6. United States Gracyn Wheeler (quarterfinals)
  7. United States Helen Pedersen (semifinals)
  8. United States Mary Greef Harris (third round)

Draw

Final eight

Quarterfinals Semifinals Finals
               
1 United States Helen Jacobs 6 6
United States Gussie Raegener 0 1
1 United States Helen Jacobs 6 6
United Kingdom Kay Stammers 4 3
4 United States Carolin Babcock 5 6 4
United Kingdom Kay Stammers 7 3 6
1 United States Helen Jacobs 6 3 2
3 United States Alice Marble 4 6 6
United States Dorothy Bundy 3 6 4
7 United States Helen Pedersen 6 4 6
7 United States Helen Pedersen 0 1
3 United States Alice Marble 6 6
3 United States Alice Marble 6 11
6 United States Gracyn Wheeler 2 9
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References

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