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2018 Big Ten men's lacrosse tournament
From Wikipedia, the free encyclopedia
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The 2018 Big Ten Men's Lacrosse Tournament was held May 3 and May 5 at U-M Lacrosse Stadium in Ann Arbor, Michigan. The winner of the tournament received the Big Ten Conference's automatic bid to the 2018 NCAA Division I Men's Lacrosse Championship. Four teams from the Big Ten conference competed in the single elimination event. The seeds were determined based upon the teams' regular season conference record.[1] Johns Hopkins won the tournament, beating Maryland 13-10.[2][3]
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Standings
Only the top four teams in the Big Ten Conference advanced to the Big Ten Conference Tournament.[4][5]
Not including Big Ten Tournament and NCAA tournament results
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Schedule
Bracket
U-M Lacrosse Stadium – Ann Arbor, Michigan
Semifinals May 3 | Championship Game May 5 | ||||||||
1 | Maryland | 12 | |||||||
4 | Rutgers | 9 | |||||||
1 | Maryland | 10 | |||||||
2 | Johns Hopkins | 13 | |||||||
2 | Johns Hopkins | 6 | |||||||
3 | Ohio State | 5 |
Awards
- MVP: Brock Turnbaugh, Johns Hopkins, Goalie
- All-Tournament Team:
- Logan Wisnauskas, Maryland, Attack
- Connor Kelly, Maryland, Midfield
- Matt Neufeldt, Maryland, Defense
- Brock Turnbaugh, Johns Hopkins, Goalie
- Kyle Marr, Johns Hopkins, Attack
- Cole Williams, Johns Hopkins, Attack
- Patrick Foley, Johns Hopkins, Defense
- Robert Kuhn, Johns Hopkins, Defense
- Alex Bronzo, Rutgers, Defense
- Erik Evans, Ohio State, Defense
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References
External links
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