2019 Surbiton Trophy – Women's doubles

Jessica Moore and Ellen Perez were the defending champions,^[1] but chose to participate with different partners. Moore partnered alongside Monique Adamczak but lost in the first round to Viktorija Golubic and Ingrid Neel. Perez partnered alongside Arina Rodionova but lost in the first round to Naiktha Bains and Naomi Broady.

Women's doubles
2019 Surbiton Trophy
Champions	Jennifer Brady Caroline Dolehide
Runners-up	Heather Watson Yanina Wickmayer
Score	6–3, 6–4

Main article: 2019 Surbiton Trophy

Jennifer Brady and Caroline Dolehide won the title, defeating Heather Watson and Yanina Wickmayer in the final, 6–3, 6–4.^[2]

Seeds

1. Asia Muhammad / Giuliana Olmos (quarterfinals)
2. Monique Adamczak / Jessica Moore (first round)
3. Anna Blinkova / Oksana Kalashnikova (first round)
4. Ellen Perez / Arina Rodionova (first round)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• Alt = Alternate
• ITF = ITF entry
• PR = Protected ranking
• SR = Special ranking
• SE = Special exempt
• JE = Junior exempt
• JR = Junior Accelerator Programme entrant
• CO = College Accelerator Programme entrant
• NG = Next Gen Accelerator Program entrant
• w/o = Walkover
• r = Retired
• d = Defaulted

Draw

	First round							Quarterfinals							Semifinals							Final
	1	A Muhammad G Olmos	3	77	[10]
		S Santamaria L Stefani	6	65	[6]			1	A Muhammad G Olmos	63	3
		J Brady C Dolehide	6	6					J Brady C Dolehide	77	6
	WC	SB Grey E Silva	4	4												J Brady C Dolehide	6	6
	3	A Blinkova O Kalashnikova	3	63												M Brengle S Vickery	2	2
		M Brengle S Vickery	6	77					M Brengle S Vickery	w/o
		A Guarachi E Routliffe	64	6	[4]			WC	K Dunne E Webley-Smith
	WC	K Dunne E Webley-Smith	77	2	[10]																		J Brady C Dolehide	6	6
		H Watson Y Wickmayer	6	5	[10]																		H Watson Y Wickmayer	3	4
		Q Gleason M Sanchez	3	7	[5]				H Watson Y Wickmayer	6	3	[10]
	WC	N Bains N Broady	6	6				WC	N Bains N Broady	4	6	[8]
	4	E Perez Ar Rodionova	4	1												H Watson Y Wickmayer	4	6	[11]
		M Kato L Zhu	2	3												I Jorović T Smitková	6	3	[9]
		I Jorović T Smitková	6	6					I Jorović T Smitková	77	6
		V Golubic I Neel	2	6	[10]				V Golubic I Neel	65	4
	2	M Adamczak J Moore	6	3	[7]