The angular functions satisfy the coupled eigenvalue equations,[3]

where
is the particle's rest mass (measured in units so that it is the inverse of the Compton wavelength), and


Eliminating
between the two equations, one obtains

The function
satisfies the adjoint equation, that can be obtained from the above equation by replacing
with
. The boundary conditions for these second-order differential equations are that
(and
) be regular at
and
. The eigenvalue problem presented here in general requires numerical integrations for it to be solved.
Properties and limiting solutions
The eigenvalue problem depends on two continuous parameters, namely
and
. For a given
and
, the eigenstates are characterised by three discrete numbers: the particle angular momentum,
, its azimuthal component
and the parity
The spectrum elements may then be explicitly labelled as[4]

The eigenvalue
has the physical interpretation of being the sqaure root of the generalised total anagular momentum squared.[5] The knowledge of the spectrum in the positive quadrant
is sufficient to determine the full spectrum, as implied by the symmetry:

Furthermore

and the combinations thereof.
Non-rotating black hole (Schwarzschild black hole)
: The problem can be solved explicitly. The eigenvalues and eigenfunctions are given by


where
is the associated Legendre polynomials and

Special case
: For the special case where
, the solutions are given by[6]


where
![{\displaystyle c_{j,m,{\mathcal {P}}}^{(a\omega ,a\omega )}=[(j+{\mathcal {P}}/2+1/2)^{2}-m^{2}]/(\lambda _{j,m,{\mathcal {P}}}^{(a\omega ,a\omega )}+m+1/2-a\omega ),\quad A={\sqrt {{\frac {(j+{\mathcal {P}}/2+1/2)}{2\pi }}{\frac {(j+{\mathcal {P}}/2-m-1/2)!}{(j+{\mathcal {P}}/2+m+1/2)!}}\left(1+{\frac {{\mathcal {P}}(m-a\omega )}{\sqrt {(j+{\mathcal {P}}/2+1/2)^{2}-2ma\omega +a^{2}\omega ^{2}}}}\right)}}.}](//wikimedia.org/api/rest_v1/media/math/render/svg/5728f8e898e11d8e63fddc85be6d6e81df5607d6)
When
, we have


where
![{\displaystyle c_{j,m,{\mathcal {P}}}^{(a\omega ,-a\omega )}=-[(j-{\mathcal {P}}/2+1/2)^{2}-m^{2}]/(-\lambda _{j,m,{\mathcal {P}}}^{(a\omega ,-a\omega )}+m+1/2-a\omega ),\quad A={\sqrt {{\frac {(j-{\mathcal {P}}/2+1/2)}{2\pi }}{\frac {(j-{\mathcal {P}}/2-m-1/2)!}{(j-{\mathcal {P}}/2+m+1/2)!}}\left(1-{\frac {{\mathcal {P}}(m-a\omega )}{\sqrt {(j-{\mathcal {P}}/2+1/2)^{2}-2ma\omega +a^{2}\omega ^{2}}}}\right)}}.}](//wikimedia.org/api/rest_v1/media/math/render/svg/49ca855388379de1acb2fb70ea53647d22577e3c)