Dennebrœucq

Dennebrœucq (French pronunciation: [dɛnbʁœk]; West Flemish: Denebroek) is a commune in the Pas-de-Calais department in the Hauts-de-France region of France^[2] 12 miles (19 km) south of Saint-Omer The medieval Flemish name was Denebroek^[3]

Map of the commune and adjacent places

Dennebrœucq Denebroek
Commune
The church of Dennebrœucq
Coat of arms
Location of Dennebrœucq
Dennebrœucq Show map of France Dennebrœucq Show map of Hauts-de-France
Coordinates: 50°34′27″N 2°09′14″E
Country	France
Region	Hauts-de-France
Department	Pas-de-Calais
Arrondissement	Saint-Omer
Canton	Fruges
Intercommunality	Pays de Saint-Omer
Government
• Mayor (2020–2026)	Christian Crunelle[1]
Area 1	3.73 km2 (1.44 sq mi)
Population  (2021)	397
• Density	106/km2 (276/sq mi)
Time zone	UTC+01:00 (CET)
• Summer (DST)	UTC+02:00 (CEST)
INSEE/Postal code	62267 /62560
Elevation	53–140 m (174–459 ft) (avg. 70 m or 230 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Population

Historical population

Year	Pop.	±% p.a.
1968	279	—
1975	257	−1.17%
1982	269	+0.65%
1990	310	+1.79%
1999	314	+0.14%
2007	356	+1.58%
2012	369	+0.72%
2017	389	+1.06%
Source: INSEE[4]

See also

• Communes of the Pas-de-Calais department