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Diiodine tetroxide

Chemical compound From Wikipedia, the free encyclopedia

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Diiodine tetraoxide, I2O4, is a chemical compound of oxygen and iodine. It belongs to the class of iodine oxides, and is a mixed oxide, consisting of iodine(III) and iodine(V) oxidation states.

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Synthesis

The oxide is formed by the reaction of hot concentrated sulfuric acid on iodic acid for several days.[2]

3HIO3 → I2O4 + HIO4 + H2O

It is formed from diiodine pentoxide and iodine in concentrated sulfuric acid or iodosyl sulfate (IO)2SO4 added to water:[3]

4(IO)2SO4 + 4H2O → 3I2O4 + I2 + 4H2SO4

Alternatively, excess of concentrated nitric acid oxidizes dry iodine to this salt.[4]

Physical properties

Diiodine tetraoxide is a yellow, granular powder. At temperatures above 85 °C it decomposes to diiodine pentoxide and iodine:[2]

5I2O4 → 4I2O5 + I2

This process is even faster at 135 °C. It dissolves in hot water to form iodate and iodide.[2] Structurally, the compound is an iodyl iodite O2I-OIO (iodine(V,III) oxide)[2] with bent IVO2 units (I–O distances 1.80 and 1.85 Å; ∠OIO angle 97°) and bent IIIIO2 units (IO distances 1.93 Å, OIO angle 95.8°). Both units are linked via I—O—I bridges to form polymeric zigzag chains (I2O4)x.[2]

Diiodine tetraoxide has a monoclinic crystal structure with the space group P21/c (space group number 14). Unit cell dimensions are a = 8.483 b = 6.696 c = 8.333 Å and β = 124.69°. Unit cell volume = 389.15 Å3. Z = 4. Density is 2.57 Mg/m3[3][5]

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Reactions

Diiodine tetroxide oxidises hydrochloric acid:[6]

I2O4 + 8H+ + 8Cl → 2ICl + 4H2O + 3Cl2

It decomposes[vague] in water.[4][7]

References

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