Iridium(IV) iodide

Iridium(IV) iodide is a binary chemical compound of iridium and iodide with the chemical formula IrI
₄.^[1][2][3]

Iridium(IV) iodide

Names
Other names Iridium(IV) iodide, tetraiodoiridium
Identifiers
CAS Number	7790-45-6
3D model (JSmol)	Interactive image
ChemSpider	22504631
ECHA InfoCard	100.029.279
EC Number	232-206-3
PubChem CID	25113453
CompTox Dashboard (EPA)	DTXSID70999093
InChI InChI=1S/4HI.Ir/h4*1H;/q;;;;+4/p-4 Key: BUUWLOZTIYBNKB-UHFFFAOYSA-J
SMILES I[Ir](I)(I)I
Properties
Chemical formula	I4Ir
Molar mass	699.835 g·mol−1
Appearance	Black powder
Melting point	100 °C (212 °F; 373 K)
Solubility in water	insoluble
Structure
Crystal structure	hexagonal
Related compounds
Related compounds	Iridium triiodide, platinum tetraiodide
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). Infobox references

Preparation

Iridium(IV) iodide can be obtained by reacting dipotassium hexachloroiridate or hexachloroiridic acid with an aqueous solution of potassium iodide.^[4][5]

Properties

Iridium tetraiodide forms black crystals, does not dissolve in water and alcohol.^[6][7][8] In alkali metal iodide solutions, the compound dissolves easily to give a ruby red solution, forming complex salts.^[5]

The compound decomposes when heated:^{[citation needed]}

IrI₄ → Ir + 2I₂

Uses

Iridium(IV) iodide can be used as a catalyst in organic chemistry.^[9][8]