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Lutetium(III) fluoride
Chemical compound From Wikipedia, the free encyclopedia
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Lutetium(III) fluoride is an inorganic compound with a chemical formula LuF3.
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Production
Lutetium(III) fluoride can be produced by reacting lutetium oxide with hydrogen fluoride, or reacting lutetium chloride and hydrofluoric acid:[3]
- Lu2O3 + 6 HF → 2 LuF3 + 3 H2O
- LuCl3 + 3 HF → LuF3 + 3 HCl
It can also be produced by reacting lutetium sulfide and hydrofluoric acid:[4]
- 3 Lu
2S
3+ 20 HF + (2 + 2x) H
2O → 2 (H
3O)Lu
3F
10·xH
2O↓ + 9 H
2S↑ (x = 0.9) - (H3O)Lu3F10 → 3 LuF3 + HF↑ + H2O↑
Lutetium oxide and nitrogen trifluoride react at 240 °C to produce LuOF. A second step happens below 460 °C to produce LuF3.[5]
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References
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