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Misra–Gries summary
Mathematical algorithm From Wikipedia, the free encyclopedia
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In the field of streaming algorithms, Misra–Gries summaries are used to solve the frequent elements problem in the data stream model. That is, given a long stream of input that can only be examined once (and in some arbitrary order), the Misra-Gries algorithm[1] can be used to compute which (if any) value makes up a majority of the stream, or more generally, the set of items that constitute some fixed fraction of the stream.
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The term "summary" is due to Graham Cormode.[2][3] The algorithm was presented by Misra and Gries alongside a different algorithm for finding frequent elements, the Misra–Gries heavy hitters algorithm.
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The Misra–Gries summary
As for all algorithms in the data stream model, the input is a finite sequence of integers from a finite domain. The algorithm outputs an associative array which has values from the stream as keys, and estimates of their frequency as the corresponding values. It takes a parameter k which determines the size of the array, which impacts both the quality of the estimates and the amount of memory used.
algorithm misra-gries:[4] input: A positive integer k A finite sequence s taking values in the range 1,2,...,m output: An associative array A with frequency estimates for each item in s A := new (empty) associative array while s is not empty: take a value i from s if i is in keys(A): A[i] := A[i] + 1 else if |keys(A)| < k - 1: A[i] := 1 else: for each K in keys(A): A[K] := A[K] - 1 if A[K] = 0: remove K from keys(A) return A
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Properties
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The Misra–Gries algorithm uses O(k(log(m)+log(n))) space, where m is the number of distinct values in the stream and n is the length of the stream. The factor k accounts for the number of entries that are kept in the associative array A. Each entry consists of a value i and an associated counter c. The counter c can, in principle, take any value in {0,...,n}, which requires ⌈log(n+1)⌉ bits to store. Assuming that the values i are integers in {0,...,m-1}, storing them requires ⌈log(m)⌉ bits.
Every item which occurs more than n/k times is guaranteed to appear in the output array.[4] Therefore, in a second pass over the data, the exact frequencies for the k−1 items can be computed to solve the frequent items problem, or in the case of k=2, the majority problem. With the same arguments as above, this second pass also takes O(k(log(m)+log(n))) space.
The summaries (arrays) output by the algorithm are mergeable, in the sense that combining summaries of two streams s and r by adding their arrays keywise and then decrementing each counter in the resulting array until only k keys remain results in a summary of the same (or better) quality as compared to running the Misra-Gries algorithm over the concatenation of s with r.
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Example
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Let k=2 and the data stream be 1,4,5,4,4,5,4,4 (n=8,m=5). Note that 4 is appearing 5 times in the data stream which is more than n/k=4 times and thus should appear as the output of the algorithm.
Since k=2 and |keys(A)|=k−1=1 the algorithm can only have one key with its corresponding value. The algorithm will then execute as follows(- signifies that no key is present):
Output: 4
References
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