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Tin(IV) bromide
Chemical compound From Wikipedia, the free encyclopedia
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Tin(IV) bromide is the chemical compound SnBr4. It is a colourless low melting solid.[1]
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Structure
SnBr4 crystallises in a monoclinic crystal system with molecular SnBr4 units that have distorted tetrahedral geometry.[2] The mean Sn-Br bond length is 242.3 pm.[3]
Preparation
SnBr4 can be prepared by reaction of the elements at standard temperature and pressure (STP):[4][page needed]
- Sn + 2Br
2 → SnBr
4
Reactions
In aqueous solution SnBr4 dissolves to give a series of octahedral (six-ligated) bromo-aquo complexes. These include SnBr4(H2O)2 and cis- and trans-[SnBr2(H2O)4]2+.[5]
SnBr4 forms 1:1 and 1:2 complexes with ligands. With trimethylphosphine both SnBr4·P(CH3)3 and SnBr4·2P(CH3)3.[6]
Tin(IV) bromide undergoes redistribution with tin(IV) chloride as assessed by 119Sn NMR and Raman spectroscopy. Equilibrium is achieved in seconds at room temperature. By contrast, halide exchange for related germanium and especially silicon halides is slower.[7]
References
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