1892 United States House of Representatives election in Wyoming

The Wyoming United States House election for 1892 was held on November 3, 1892. Democratic Henry A. Coffeen defeated Republican incumbent Clarence D. Clark with 51.34% of the vote making Clark the first incumbent Representative from Wyoming to lose reelection.

1892 United States House of Representatives election in Wyoming

← 1890 November 8, 1892 (1892-11-08) 1894 →

Nominee Henry A. Coffeen Clarence D. Clark Party Democratic Republican Popular vote 8,855 8,394 Percentage 51.34% 48.66%

County results Coffeen:      50–60%      60–70% Clark:      50–60%      No Data

U.S. Representative before election Clarence D. Clark Republican Elected U.S. Representative Henry A. Coffeen Democratic

Results

United States House of Representatives election in Wyoming, 1892^[1]

Party		Candidate	Votes	%
	Democratic	Henry A. Coffeen	8,855	51.34%
	Republican	Clarence D. Clark (inc.)	8,394	48.66%
Total votes			17,249	100%