在機率論中,伯恩施坦不等式(Bernstein inequalities)給出了隨機變數的和對平均值偏離的機率。在最簡單的情況下,設 X 1 , ⋯ , X n {\displaystyle X_{1},\cdots ,X_{n}} 是獨立的伯努利隨機變數,取值+1和-1的機率各是1/2,則對任意正數 ε {\displaystyle \varepsilon } P ( | 1 n ∑ i = 1 n X i | > ε ) ≤ 2 exp ( − n ε 2 2 ( 1 + ε / 3 ) ) {\displaystyle \mathbb {P} \left(\left|{\frac {1}{n}}\sum _{i=1}^{n}{X_{i}}\right|>\varepsilon \right)\leq 2\exp {\left(-{\frac {n\varepsilon ^{2}}{2(1+\varepsilon /3)}}\right)}} 伯恩施坦不等式由謝爾蓋·伯恩施坦於1920年代證明,並於1930年代發表[1][2][3][4]。之後,這些不等式多次被其他數學家獨立地發現。因此,伯恩施坦不等式的一些特例也被稱為Chernoff界,Hoeffding不等式,以及吾妻不等式。 Remove ads不等式 1.設 X 1 , ⋯ , X n {\displaystyle X_{1},\cdots ,X_{n}} 是數學期望值為0的獨立的隨機變數。若對所有 i {\displaystyle i} , | X i | ≤ M {\displaystyle |X_{i}|\leq M} 幾乎必然成立,則對任意正數 t {\displaystyle t} P ( ∑ i = 1 n X i > t ) ≤ exp ( − t 2 / 2 ∑ E X j 2 + M t / 3 ) {\displaystyle \mathbb {P} \left(\sum _{i=1}^{n}{X_{i}}>t\right)\leq \exp {\left(-{\frac {t^{2}/2}{\sum {\mathbb {E} X_{j}^{2}}+Mt/3}}\right)}} 2.設 X 1 , ⋯ , X n {\displaystyle X_{1},\cdots ,X_{n}} 是獨立的隨機變數。若存在正實數 L {\displaystyle L} ,使得對任意整數 k > 1 {\displaystyle k>1} ,都有 E | X i k | ≤ 1 2 k ! L k − 2 E X i 2 {\displaystyle \mathbb {E} |X_{i}^{k}|\leq {\frac {1}{2}}k!L^{k-2}\mathbb {E} X_{i}^{2}} ,則對 0 < t < 1 2 L ∑ E X j 2 {\displaystyle 0<t<{\frac {1}{2L}}{\sqrt {\sum {\mathbb {E} X_{j}^{2}}}}} P ( ∑ i = 1 n X i ≥ 2 t ∑ E X i 2 ) < exp ( − t 2 ) {\displaystyle \mathbb {P} \left(\sum _{i=1}^{n}{X_{i}}\geq 2t{\sqrt {\sum {\mathbb {E} X_{i}^{2}}}}\right)<\exp {(-t^{2})}} 3.設 X 1 , ⋯ , X n {\displaystyle X_{1},\cdots ,X_{n}} 是獨立的隨機變數。若對任意整數 k ≥ 4 {\displaystyle k\geq 4} ,都有 E | X i k | ≤ k ! 4 ! ( L 5 ) k − 4 {\displaystyle \mathbb {E} |X_{i}^{k}|\leq {\frac {k!}{4!}}\left({\frac {L}{5}}\right)^{k-4}} ,記 A k = ∑ i = 1 n E X i k {\displaystyle A_{k}=\sum _{i=1}^{n}{\mathbb {E} X_{i}^{k}}} ,則對於 0 < t ≤ 5 2 A 2 4 L {\displaystyle 0<t\leq {\frac {5{\sqrt {2A_{2}}}}{4L}}} P ( | ∑ j = 1 n X j − A 3 t 2 3 A 2 | ≥ 2 A 2 t ( 1 + A 4 t 2 6 A 2 2 ) ) < 2 exp ( − t 2 ) {\displaystyle \mathbb {P} \left(\left|\sum _{j=1}^{n}{X_{j}}-{\frac {A_{3}t^{2}}{3A_{2}}}\right|\geq {\sqrt {2A_{2}}}t\left(1+{\frac {A_{4}t^{2}}{6A_{2}^{2}}}\right)\right)<2\exp {(-t^{2})}} 4.伯恩施坦也把以上不等式推廣到弱相關隨機變數的情況。例如,不等式(2)可以推廣成以下形式。 X 1 , ⋯ , X n {\displaystyle X_{1},\cdots ,X_{n}} 可以不是獨立隨機變數。若對任意正整數 i {\displaystyle i} , E ( X i | X 1 , ⋯ , X i − 1 ) = 0 , {\displaystyle \mathbb {E} (X_{i}|X_{1},\cdots ,X_{i-1})=0,} E ( X i 2 | X 1 , ⋯ , X i − 1 ) ≤ R i E X i 2 , {\displaystyle \mathbb {E} (X_{i}^{2}|X_{1},\cdots ,X_{i-1})\leq R_{i}\mathbb {E} X_{i}^{2},} E ( X i k | X 1 , ⋯ , X i − 1 ) ≤ k ! L k − 2 2 E ( X i 2 | X 1 , ⋯ , X i − 1 ) , {\displaystyle \mathbb {E} (X_{i}^{k}|X_{1},\cdots ,X_{i-1})\leq {\frac {k!L^{k-2}}{2}}\mathbb {E} (X_{i}^{2}|X_{1},\cdots ,X_{i-1}),} 則對於 0 < t < 1 2 L ∑ i = 1 n R i E X i 2 {\displaystyle 0<t<{\frac {1}{2L}}{\sqrt {\sum _{i=1}^{n}{R_{i}\mathbb {E} X_{i}^{2}}}}} , P ( ∑ i = 1 n X i ≥ 2 t ∑ i = 1 n R i E X i 2 ) < exp ( − t 2 ) {\displaystyle \mathbb {P} \left(\sum _{i=1}^{n}{X_{i}}\geq 2t{\sqrt {\sum _{i=1}^{n}{R_{i}\mathbb {E} X_{i}^{2}}}}\right)<\exp {(-t^{2})}} Remove ads另見 集中不等式 參考資料Loading content...Loading related searches...Wikiwand - on Seamless Wikipedia browsing. On steroids.Remove ads