Montécheroux
Commune in Bourgogne-Franche-Comté, France From Wikipedia, the free encyclopedia
Commune in Bourgogne-Franche-Comté, France From Wikipedia, the free encyclopedia
Montécheroux is a commune in the Doubs department in the Bourgogne-Franche-Comté region in eastern France.
Montécheroux | |
---|---|
Coordinates: 47°21′02″N 6°48′24″E | |
Country | France |
Region | Bourgogne-Franche-Comté |
Department | Doubs |
Arrondissement | Montbéliard |
Canton | Maîche |
Government | |
• Mayor (2020–2026) | Leon Bonvalot[1] |
Area 1 | 13.13 km2 (5.07 sq mi) |
Population (2021)[2] | 551 |
• Density | 42/km2 (110/sq mi) |
Time zone | UTC+01:00 (CET) |
• Summer (DST) | UTC+02:00 (CEST) |
INSEE/Postal code | 25393 /25190 |
Elevation | 420–830 m (1,380–2,720 ft) |
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries. |
The commune lies 7 km (4.3 mi) from Saint-Hippolyte.
Year | Pop. | ±% |
---|---|---|
1962 | 548 | — |
1968 | 550 | +0.4% |
1975 | 542 | −1.5% |
1982 | 571 | +5.4% |
1990 | 548 | −4.0% |
1999 | 545 | −0.5% |
2008 | 563 | +3.3% |
2012 | 581 | +3.2% |
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