Ross Township, Lake County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
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Ross Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 47,890 and it contained 19,951 housing units.[4]
More information Census, Pop. ...
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 1,427 | — | |
1900 | 1,542 | 8.1% | |
1910 | 1,434 | −7.0% | |
1920 | 1,440 | 0.4% | |
1930 | 1,996 | 38.6% | |
1940 | 3,482 | 74.4% | |
1950 | 6,676 | 91.7% | |
1960 | 14,854 | 122.5% | |
1970 | 28,845 | 94.2% | |
1980 | 34,842 | 20.8% | |
1990 | 34,683 | −0.5% | |
2000 | 38,685 | 11.5% | |
2010 | 47,890 | 23.8% | |
2020 | 48,529 | 1.3% | |
Source: US Decennial Census[5] |
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Quick Facts Country, State ...
Ross Township | |
---|---|
Coordinates: 41°28′19″N 87°18′41″W | |
Country | United States |
State | Indiana |
County | Lake |
founded | 1848 |
Named for | William Ross |
Government | |
• Type | Indiana township |
Area | |
• Total | 49.09 sq mi (127.1 km2) |
• Land | 49.05 sq mi (127.0 km2) |
• Water | 0.04 sq mi (0.1 km2) |
Elevation | 669 ft (204 m) |
Population | |
• Total | 48,529 |
• Density | 976.3/sq mi (377.0/km2) |
FIPS code | 18-66096[3] |
GNIS feature ID | 453814 |
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