Tignall, Georgia
Town in Georgia, United States From Wikipedia, the free encyclopedia
Town in Georgia, United States From Wikipedia, the free encyclopedia
Tignall is a town in Wilkes County, Georgia, United States. The population was 485 in 2020.
Tignall, Georgia | |
---|---|
Nickname: Little Atlanta, | |
Motto: "I'd rather be in Tignall" | |
Coordinates: 33°52′1″N 82°44′28″W | |
Country | United States |
State | Georgia |
County | Wilkes |
Area | |
• Total | 2.79 sq mi (7.23 km2) |
• Land | 2.75 sq mi (7.13 km2) |
• Water | 0.04 sq mi (0.10 km2) |
Elevation | 640 ft (191 m) |
Population (2020) | |
• Total | 485 |
• Density | 176.11/sq mi (67.99/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 30668 |
Area code | 706 |
FIPS code | 13-76532[2] |
GNIS feature ID | 0356591[3] |
The Georgia General Assembly incorporated Tignall as a town in 1907.[4] It was named for Tignall Livingston Moss, a lieutenant in the Confederate army who was killed in battle in 1862.[5]
Tignall is located at 33°52′1″N 82°44′28″W (33.866861, -82.741195).[6] The town lies along Georgia State Route 17 south of Elberton and north of Washington, and a few miles west of the Georgia-South Carolina state line. According to the United States Census Bureau, the town has a total area of 2.9 square miles (7.5 km2), all land.
As of the census[2] of 2010, there were 615 people, 279 households, and 179 families residing in the town. By 2020, its population was 485.
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