1810 Delaware gubernatorial election

For related races, see 1810 United States gubernatorial elections.

The 1810 Delaware gubernatorial election was held on October 2, 1810.

1810 Delaware gubernatorial election

← 1807 October 2, 1810 1813 →

Nominee Joseph Haslet Daniel Rodney Party Democratic-Republican Federalist Popular vote 3,664 3,593 Percentage 50.49% 49.51%

Haslet:      60–70% Rodney:      50–60%      60–70%

Governor before election George Truitt Federalist Elected Governor Joseph Haslet Democratic-Republican

Incumbent Federalist Governor George Truitt was not eligible for re-election under the Delaware Constitution of 1792.

Democratic-Republican nominee Joseph Haslet defeated Federalist nominee Daniel Rodney with 50.49% of the vote.

General election

Results

1810 Delaware gubernatorial election^[1][2][3][4]

Party		Candidate	Votes	%	±%
	Democratic-Republican	Joseph Haslet	3,664	50.49%
	Federalist	Daniel Rodney	3,593	49.51%
Majority			71	0.98%
Turnout			7,257	100.00%
	Democratic-Republican gain from Federalist		Swing