1824 United States presidential election in Virginia

Main article: 1824 United States presidential election

The 1824 United States presidential election in Virginia took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 24 representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in Virginia

← 1820 October 26 – December 2, 1824 1828 →

Nominee William H. Crawford John Quincy Adams Andrew Jackson Party Democratic-Republican Democratic-Republican Democratic-Republican Home state Georgia Massachusetts Tennessee Running mate Nathaniel Macon John C. Calhoun John C. Calhoun Electoral vote 24 0 0 Popular vote 8,558 3,419 2,975 Percentage 55.68% 22.24% 19.35%

County Results Crawford   30–40%   40–50%   50–60%   60–70%   70–80%   80–90%   90–100% Adams   30–40%   40–50%   50–60%   60–70%   70–80% Jackson   40–50%   50–60%   60–70%   70–80% Clay   30–40%   80–90% Tie   40–50% No Data/Vote

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and 4 candidates from this party sought the Presidency. Virginia voted for William H. Crawford over John Quincy Adams, Andrew Jackson, and Henry Clay. Crawford won Virginia by a margin of 33.44%.

Results

1824 United States presidential election in Virginia[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	William H. Crawford	8,558	55.68%	24
	Democratic-Republican	John Quincy Adams	3,419	22.24%	0
	Democratic-Republican	Andrew Jackson	2,975	19.35%	0
	Democratic-Republican	Henry Clay	419	2.73%	0
Totals			15,371	100.0%	24