1828 United States presidential election in Connecticut

Main article: 1828 United States presidential election

The 1828 United States presidential election in Connecticut took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

1828 United States presidential election in Connecticut

← 1824 October 31 – December 2, 1828 1832 →

Nominee John Quincy Adams Andrew Jackson Party National Republican Democratic Home state Massachusetts Tennessee Running mate Richard Rush John C. Calhoun Electoral vote 8 0 Popular vote 13,829 4,448 Percentage 71.36% 22.95%

County Results Adams   60–70%   70–80%   80–90%

Connecticut voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Connecticut by a margin of 48.41%.

With 71.36% of the popular vote, Connecticut would prove to be Adams' fourth strongest state in the 1828 election after Rhode Island, Massachusetts and Vermont.^[1]

Results

1828 United States presidential election in Connecticut[2]
Party		Candidate	Votes	Percentage	Electoral votes
	National Republican	John Quincy Adams (incumbent)	13,829	71.36%	8
	Democratic	Andrew Jackson	4,448	22.95%	0
	N/A	Other	1,101	5.68%	0
Totals			19,378	100.0%	8

See also

• United States presidential elections in Connecticut