1836 Rhode Island gubernatorial election

The 1836 Rhode Island gubernatorial election was held on April 20, 1836.^[1]

1836 Rhode Island gubernatorial election

← 1835 April 20, 1836 1837 →

Nominee John Brown Francis Tristam Burges Party Democratic Whig Popular vote 4,020 2,984 Percentage 56.22% 41.73%

County results Francis:      50–60%      60–70%

Governor before election John Brown Francis Democratic Elected Governor John Brown Francis Democratic

Incumbent Democratic governor John Brown Francis won re-election to a fourth term, defeating Whig nominee Tristam Burges and Constitutional Party candidate Charles Collins.

General election

Candidates

• John Brown Francis, Democratic, incumbent governor
• Tristam Burges, Whig, former U.S. representative
• Charles Collins, of Middletown, Constitutional^[2][3][4]

Results

1836 Rhode Island gubernatorial election^{[5][6][7][8][9][10][11][12]}

Party		Candidate	Votes	%	±%
	Democratic	John Brown Francis (incumbent)	4,020	56.22%
	Whig	Tristam Burges	2,984	41.73%
	Constitutional Party	Charles Collins	135	1.89%
	Scattering		12	0.17%
Majority			1,036	14.49%
Turnout			7,151
	Democratic hold		Swing