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1836 United States presidential election in Alabama

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1836 United States presidential election in Alabama
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A presidential election was held in Alabama on November 14, 1836 as part of the 1836 United States presidential election.[1] Voters chose seven representatives, or electors, to the Electoral College, who voted for President and Vice President.

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Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Alabama by a margin of 10.68%.

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Results

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Results By County

More information County, Martin Van Buren Democratic ...
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See also

References

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