1844 United States presidential election in Indiana

Main article: 1844 United States presidential election

A presidential election was held in Indiana on November 4, 1844 as part of the 1844 United States presidential election.^[1] Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.

1844 United States presidential election in Indiana

← 1840 November 4, 1844 1848 →

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Nominee James K. Polk Henry Clay Party Democratic Whig Home state Tennessee Kentucky Running mate George M. Dallas Theodore Frelinghuysen Electoral vote 12 0 Popular vote 70,181 67,867 Percentage 50.07% 48.42%

County Results Polk   40–50%   50–60%   60–70%   70–80%   80–90% Clay   40–50%   50–60%   60–70%

President before election John Tyler Independent Elected President James K. Polk Democratic

Indiana voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Indiana by a narrow margin of 1.65%.

Results

1844 United States presidential election in Indiana[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	James K. Polk of Tennessee	George M. Dallas of Pennsylvania	70,181	50.07%	12	100.00%
	Whig	Henry Clay of Kentucky	Theodore Frelinghuysen of New York	67,867	48.42%	0	0.00%
	Liberty	James G. Birney of Michigan	Thomas Morris of Ohio	2,106	1.50%	0	0.00%
Total				140,154	100.00%	12	100.00%

See also

• United States presidential elections in Indiana