1874 Rhode Island gubernatorial election

The 1874 Rhode Island gubernatorial election was held on 1 April 1874 in order to elect the governor of Rhode Island. Incumbent Republican governor Henry Howard won re-election against Democratic nominee Lyman Pierce.^[1]

1874 Rhode Island gubernatorial election

← 1873 1 April 1874 1875 →

Nominee Henry Howard Lyman Pierce Party Republican Democratic Popular vote 12,335 1,589 Percentage 87.48% 11.27%

County results Howard:      60–70%      80–90%      >90%

Governor before election Henry Howard Republican Elected Governor Henry Howard Republican

General election

On election day, 1 April 1874, incumbent Republican governor Henry Howard won re-election by a margin of 10,746 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of governor. Howard was sworn in for his second term on 5 May 1874.^[2]

Results

Rhode Island gubernatorial election, 1874

Party		Candidate	Votes	%
	Republican	Henry Howard (incumbent)	12,335	87.48
	Democratic	Lyman Pierce	1,589	11.27
		Scattering	177	1.25
Total votes			14,101	100.00
	Republican hold