1880 United States presidential election in Arkansas

The 1880 United States presidential election in Arkansas took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1880 United States presidential election

1880 United States presidential election in Arkansas

← 1876 November 2, 1880 1884 →

Nominee Winfield S. Hancock James A. Garfield Party Democratic Republican Home state Pennsylvania Ohio Running mate William H. English Chester A. Arthur Electoral vote 6 0 Popular vote 60,489 41,661 Percentage 56.13% 38.66%

County results Hancock   40–50%   50–60%   60–70%   70–80%   80–90%   90–100% Garfield   40–50%   50–60%   60–70%   70–80%   80–90% Weaver   40–50%

President before election Rutherford B. Hayes Republican Elected President James A. Garfield Republican

Arkansas voted for the Democratic nominee, Winfield Scott Hancock, over the Republican nominee, James A. Garfield by a margin of 17.47%.

Results

1880 United States presidential election in Arkansas[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Winfield Scott Hancock of Pennsylvania	William Hayden English of Arkansas	60,489	56.13%	6	100.00%
	Republican	James Abram Garfield of Ohio	Chester Alan Arthur of New York	41,661	38.66%	0	0.00%
	Greenback	James Baird Weaver of Iowa	Barzillai Jefferson Chambers of Texas	4,079	3.78%	0	0.00%
	Write-in			1,221	1.13%	0	0.00%
	Independent Democrat	A.C. Brewer of Arkansas	n/a of n/a	322	0.30%	0	0.00%
Total				107,772	100.00%	6	100.00%

See also

• United States presidential elections in Arkansas