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1892 United States presidential election in Alabama

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1892 United States presidential election in Alabama
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The 1892 United States presidential election in Alabama took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Alabama voters chose eleven electors to the Electoral College, which selected the president and vice president.

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Alabama was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. However, Weaver performed well in the South as he won counties in Alabama, Georgia, Mississippi, North Carolina, and Texas. Weaver was endorsed by a majority of Republicans in a fusion arrangement, while a minority of Republicans running a straight party ticket for Harrison.[1] Populists did best in Alabama, where electoral chicanery probably carried the day for Democrats.[2]

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Campaign

Weaver won sixteen counties, five were in the Black Belt while the remainder were white counties.[3]

Results

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Results by county

More information County, Grover Cleveland Democratic ...
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See also

Notes

  1. Because Cleveland and Weaver ran in the top two places in Alabama as a whole, margins given are Cleveland vote minus Weaver vote and Cleveland percentage minus Weaver percentage unless states otherwise.
  2. In this county where Harrison did run second ahead of Weaver, margin given is Cleveland vote minus Harrison vote and percentage margin Cleveland percentage minus Harrison percentage.

References

Works cited

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