1892 United States presidential election in Illinois

The 1892 United States presidential election in Illinois took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.

1892 United States presidential election in Illinois

← 1888 November 8, 1892 1896 →

Nominee Grover Cleveland Benjamin Harrison Party Democratic Republican Home state New York Indiana Running mate Adlai Stevenson I Whitelaw Reid Electoral vote 24 0 Popular vote 426,281 399,288 Percentage 48.79% 45.70%

County Results Cleveland   40–50%   50–60%   60–70% Harrison   40–50%   50–60%   60–70%   70–80%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

Illinois was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. This marked the first time a Democratic candidate won Illinois since 1856 when James Buchanan carried the state. This makes Illinois one of three states (along with California and Wisconsin) that Cleveland lost in his first two electoral bids but won in his third.

Results

1892 United States presidential election in Illinois[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Grover Cleveland	426,281	48.79%	24
	Republican	Benjamin Harrison (incumbent)	399,288	45.70%	0
	Prohibition	John Bidwell	25,871	2.96%	0
	Populist	James B. Weaver	22,207	2.54%	0
Totals			873,647	100.00%	24
Voter turnout					—

See also

• United States presidential elections in Illinois

Notes