1899 Iowa gubernatorial election

The 1899 Iowa gubernatorial election was held on November 7, 1899. Incumbent Republican L. M. Shaw defeated Democratic nominee Frederick Edward White with 55.26% of the vote.

1899 Iowa gubernatorial election

← 1897 November 7, 1899 1901 →

Nominee L. M. Shaw Frederick Edward White Party Republican Democratic Popular vote 239,464 183,301 Percentage 55.26% 42.30%

County results Shaw:      40-50%      50-60%      60-70%      70-80% White:      40-50%      50-60%

Governor before election L. M. Shaw Republican Elected Governor L. M. Shaw Republican

General election

Candidates

Major party candidates

• L. M. Shaw, Republican
• Frederick Edward White, Democratic

Other candidates

• Marshall W. Atwood, Prohibition
• Charles Lloyd, People's
• M. J. Kremer, Socialist Labor
• C. C. Heacock, United Christian

Results

1899 Iowa gubernatorial election^[1]

Party		Candidate	Votes	%	±%
	Republican	L. M. Shaw (incumbent)	239,464	55.26%
	Democratic	Frederick Edward White	183,301	42.30%
	Prohibition	Marshall W. Atwood	7,639	1.76%
	Populist	Charles Lloyd	1,698	0.39%
	Socialist Labor	M. J. Kremer	757	0.18%
	Independent	C. C. Heacock	484	0.11%
Majority			56,163
Turnout
	Republican hold		Swing