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1900 United States presidential election in Wyoming
From Wikipedia, the free encyclopedia
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The 1900 United States presidential election in Wyoming took place on November 6, 1900, as part of the 1900 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.
Wyoming was won by the President William McKinley (R–Ohio), running with the 33rd Governor of New York, Theodore Roosevelt, with 58.66 percent of the popular vote, against representative William Jennings Bryan (D–Nebraska), running with the 23rd Vice President Adlai Stevenson I, with 41.17 percent of the popular vote.[1] McKinley won the state by a margin of 17.49%
McKinley had previously lost Wyoming to Bryan four years earlier while Bryan would later go on to lose the state again to William Howard Taft in 1908.
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Results
Results by county
Counties that flipped from Democratic to Republican
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See also
Notes
- The Wyoming Blue Book, Volume II lists Esperson as having been a Populist or Prohibitionist, but this makes no sense. Esperson's votes match those of Wood and Cook exactly except for one precinct in Sheridan County; this almost certainly indicates that his votes were on the same ticket as those of Wood and Cook. Moreover, Esperson was on the Socialist ticket as a presidential elector in 1904. Thus, there was no Populist or Prohibition vote in Wyoming in 1900.
References
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