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1912 United States presidential election in Wyoming

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1912 United States presidential election in Wyoming
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The 1912 United States presidential election in Wyoming took place on November 5, 1912, as part of the 1912 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

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Wyoming was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 36.20 percent of the popular vote, against the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 34.42 percent of the popular vote, the 26th president of the United States Theodore Roosevelt (PNew York), running with governor of California Hiram Johnson, with 21.83 percent of the popular vote and the five-time candidate of the Socialist Party of America for President of the United States Eugene V. Debs (SIndiana), running with the first Socialist mayor of a major city in the United States Emil Seidel, with 6.53 percent of the popular vote.[1]

Despite having a member of the Progressive Party (Joseph M. Carey) as the governor of the state, Theodore Roosevelt came in third and Wyoming was one of the areas Roosevelt received lower levels of support.

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Results

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Results by county

More information County, Woodrow Wilson Democrat ...

Counties that flipped from Republican to Democratic

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See also

Notes

  1. Based on totals for highest elector on each ticket
  2. Based on highest elector on each ticket
  3. In this county where Roosevelt ran second ahead of Taft, margin given is Wilson vote minus Roosevelt vote and percentage margin Wilson percentage minus Roosevelt percentage.

References

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