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1946 Davis Cup

1946 edition of the Davis Cup From Wikipedia, the free encyclopedia

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The 1946 Davis Cup was the 35th edition of the most important tournament between national teams in men's tennis. The trophy and tournament were renamed for the founder, Dwight F. Davis, upon his death in 1945. This was the first edition since the end of World War II. 15 teams entered the Europe Zone, and 5 teams entered the America Zone.

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The United States defeated Mexico in the America Zone final, and Sweden defeated Yugoslavia in the Europe Zone final. The USA defeated Sweden in the Inter-Zonal play-off, and then defeated defending champions Australia in the Challenge Round. The final was played at Kooyong Stadium in Melbourne, Australia on 26–30 December.[1][2][3]

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America Zone

Draw

Quarterfinals
14–16 June
Semifinals
13–15 June
Final
29 June–1 July
 Canada
Montreal, Canada (grass)
bye
 Canada0
 Mexico5
 Mexico
South Orange, NJ, United States (grass)
bye
 Mexico0
St. Louis, MO, United States (clay)
 United States5
 United States5
 Philippines0
 United Statesw/o
 New Zealand
bye
 New Zealand

Final

United States vs. Mexico

More information United States 5, Mexico 0 ...
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Europe Zone

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Draw

Final

Sweden vs. Yugoslavia

More information Sweden 3, Yugoslavia 2 ...
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Inter-Zonal Final

United States vs. Sweden

More information United States 5, Sweden 0 ...

Challenge Round

Australia vs. United States

More information Australia 0, United States 5 ...
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References

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