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1956 Wimbledon Championships

Tennis tournament From Wikipedia, the free encyclopedia

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The 1956 Wimbledon Championships took place on the outdoor grass courts at the All England Lawn Tennis and Croquet Club in Wimbledon, London, United Kingdom. The tournament was held from Monday 25 June until Saturday 7 July 1956.[1] It was the 70th staging of the Wimbledon Championships, and the third Grand Slam tennis event of 1956. Lew Hoad and Shirley Fry won the singles titles.

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Champions

Seniors

Men's singles

Australia Lew Hoad defeated Australia Ken Rosewall, 6–2, 4–6, 7–5, 6–4 [2]

Women's singles

United States Shirley Fry defeated United Kingdom Angela Buxton, 6–3, 6–1 [3]

Men's doubles

Australia Lew Hoad / Australia Ken Rosewall defeated Italy Nicola Pietrangeli / Italy Orlando Sirola, 7–5, 6–2, 6–1 [4]

Women's doubles

United Kingdom Angela Buxton / United States Althea Gibson defeated Australia Fay Muller / Australia Daphne Seeney, 6–1, 8–6 [5]

Mixed doubles

United States Vic Seixas / United States Shirley Fry defeated United States Gardnar Mulloy / United States Althea Gibson, 2–6, 6–2, 7–5 [6]

Juniors

Boys' singles

United States Ronnie Holmberg defeated Australia Rod Laver, 6–1, 6–1 [7]

Girls' singles

United Kingdom Ann Haydon defeated West Germany Ilse Buding, 6–3, 6–4 [8]

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References

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