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1992 United States presidential election in Michigan

From Wikipedia, the free encyclopedia

1992 United States presidential election in Michigan
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The 1992 United States presidential election in Michigan took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose 18 representatives, or electors to the Electoral College, who voted for president and vice president.

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Michigan was won by Governor Bill Clinton (D–Arkansas), with 43.77% of the popular vote, over incumbent president George H. W. Bush (R–Texas), with 36.38%. Businessman Ross Perot (I–Texas) finished in third, with 19.30% of the popular vote.[2] Clinton ultimately won the national vote, defeating incumbent president Bush.[3] This was the first time that a Democratic presidential candidate carried the state since Hubert Humphrey in 1968. It would not vote Republican again until 2016.

As of the 2024 presidential election, this is the last time that Oakland County voted for a Republican presidential candidate and the last time that Charlevoix County voted for a Democratic presidential candidate.[4] Michigan voted most similarly to the national results of the election.

This is the most recent election where Michigan voted more Republican than nearby Pennsylvania. Afterwards, Michigan would become the most Democratic of the three Rust Belt swing states (including Wisconsin and Pennsylvania) until 2024.

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Clinton on campaign. Seen here with local Democratic notables in front of Rackham School at the University of Michigan in October 1992.
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Results

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Results by county

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Counties that flipped from Republican to Democratic

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See also

References

Notes

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