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1992 United States presidential election in Minnesota

From Wikipedia, the free encyclopedia

1992 United States presidential election in Minnesota
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The 1992 United States presidential election in Minnesota took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.

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Minnesota was won by Governor Bill Clinton (D-Arkansas) with 43.48% of the popular vote over incumbent President George H. W. Bush (R-Texas) who took 31.85%, a victory margin of 11.63%. Businessman Ross Perot (I-Texas) finished third, with 23.96% of the popular vote.[2] Clinton ultimately won the national vote, defeating incumbent President Bush.[3]

April 7, 1992 saw the first presidential primary in Minnesota since 1956. Clinton won a plurality of votes in the DFL primary, and Bush won in the IR election.

Clinton became the first Democrat to win the White House without carrying Lyon or Roseau counties since Woodrow Wilson in 1912, as well as the first to do so without carrying Becker County since Woodrow Wilson in 1916.

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Results

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Results by county

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Counties that flipped from Republican to Democratic

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See also

Note

  1. In this county where Bush ran third behind Clinton and Perot, margin given is Clinton vote minus Perot vote and percentage margin Clinton percentage minus Perot percentage.
  2. In this county where Clinton ran third behind Bush and Perot, margin given is Bush vote minus Perot vote and percentage margin Bush percentage minus Perot percentage.

References

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