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2013 Knoxville Challenger – Doubles

2013 tennis event results From Wikipedia, the free encyclopedia

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Alex Kuznetsov and Mischa Zverev were the defending champions, but Zverev chose not to compete.
Kuznetsov partnered with Denys Molchanov but lost to eventual champion Samuel Groth and John-Patrick Smith in the semifinals, who also defeated Carsten Ball and Peter Polansky in the final.

Quick facts Doubles, Final ...
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Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Australia S Groth
Australia J-P Smith
6 6
Q India S Myneni
India S Singh
3 4 1 Australia S Groth
Australia J-P Smith
w/o
WC Australia Jarryd Chaplin
United States Andrew Dromsky
3 4 United States R Harrison
United States D Kudla
United States R Harrison
United States D Kudla
6 6 1 Australia S Groth
Australia J-P Smith
6 6
3 South Africa R de Voest
United States R Ram
6 7 United States A Kuznetsov
Ukraine D Molchanov
0 2
WC United States J Jenkins
United States D Novikov
1 5 3 South Africa R de Voest
United States R Ram
0 3
United Kingdom D Rice
United Kingdom S Thornley
6 3 [9] United States A Kuznetsov
Ukraine D Molchanov
6 6
United States A Kuznetsov
Ukraine D Molchanov
3 6 [11] 1 Australia S Groth
Australia J-P Smith
66 6 [10]
United States K King
United States J Sock
4 61 Australia C Ball
Canada P Polansky
77 2 [7]
Australia C Ball
Canada P Polansky
6 77 Australia C Ball
Canada P Polansky
6 6
WC United States E King
United States Dennis Nevolo
66 1 4 Republic of Ireland J Cluskey
Austria M Neuchrist
0 2
4 Republic of Ireland J Cluskey
Austria M Neuchrist
78 6 Australia C Ball
Canada P Polansky
6 77
United States S Johnson
United States T Smyczek
6 6 2 United States A Krajicek
United States T Sandgren
3 63
PR Greece T Angelinos
France Laurent Rochette
1 3 United States S Johnson
United States T Smyczek
61 4
Canada Milan Pokrajac
United States D Zivkovic
6 2 [8] 2 United States A Krajicek
United States T Sandgren
77 6
2 United States A Krajicek
United States T Sandgren
2 6 [10]
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References

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