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2014 BRD Arad Challenger – Doubles

2014 tennis event results From Wikipedia, the free encyclopedia

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Antonio Veić and Franko Škugor were the defending champions and successfully defended their title by defeating Radu Albot and Artem Sitak in the final, 6–4, 7–6(7–3).

Quick facts Doubles, Final ...
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Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Moldova R Albot
New Zealand A Sitak
6 65 [10]
WC Romania M Copil
Switzerland C Sturdza
1 77 [7] 1 Moldova R Albot
New Zealand A Sitak
6 6
WC Romania V Crivoi
Romania P Grigoriu
6 64 [10] WC Romania V Crivoi
Romania P Grigoriu
1 0
United States C Buchanan
Ecuador E Gómez
1 77 [7] 1 Moldova R Albot
New Zealand A Sitak
6 6
4 Croatia T Androić
Croatia N Mektić
6 77 4 Croatia T Androić
Croatia N Mektić
3 4
Serbia N Ćirić
Brazil F Neis
3 62 4 Croatia T Androić
Croatia N Mektić
Chile G Lama
Venezuela D Souto
4 1 Argentina G Andreozzi
Dominican Republic J Hernández
w/o
Argentina G Andreozzi
Dominican Republic J Hernández
6 6 1 Moldova R Albot
New Zealand A Sitak
4 63
Romania Alexandru-Daniel Carpen
Belarus U Ignatik
77 63 [4] 3 Croatia F Škugor
Croatia A Veić
6 77
Spain E López-Pérez
Spain DM de la Nava
64 77 [10] Spain E López-Pérez
Spain DM de la Nava
4 2
Uruguay M Cuevas
Spain P Riba
7 62 [3] 3 Croatia F Škugor
Croatia A Veić
6 6
3 Croatia F Škugor
Croatia A Veić
5 77 [10] 3 Croatia F Škugor
Croatia A Veić
6 6
Bosnia and Herzegovina D Džumhur
Bosnia and Herzegovina A Šetkić
6 6 Bosnia and Herzegovina D Džumhur
Bosnia and Herzegovina A Šetkić
4 1
Serbia I Bozoljac
Serbia N Čačić
1 4 Bosnia and Herzegovina D Džumhur
Bosnia and Herzegovina A Šetkić
6 7
WC Romania P-A Luncanu
Romania A Ungur
4 5 2 Austria S Bader
Austria G Melzer
3 5
2 Austria S Bader
Austria G Melzer
6 7
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References

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