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2018 Glasgow Trophy – Doubles

2018 tennis event results From Wikipedia, the free encyclopedia

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This was the first edition of the tournament.

Quick Facts Doubles, Final ...

Gerard Granollers and Guillermo Olaso won the title after defeating Scott Clayton and Jonny O'Mara 6–1, 7–5 in the final.

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Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 United Kingdom S Clayton
United Kingdom J O'Mara
67 6 [10]
Japan H Moriya
Japan K Uchida
79 2 [5] 1 United Kingdom S Clayton
United Kingdom J O'Mara
6 6
PR United Kingdom L Glasspool
United Kingdom J Ward
65 6 [6] PR United States JP Fruttero
Netherlands I Sijsling
4 2
PR United States JP Fruttero
Netherlands I Sijsling
77 2 [10] 1 United Kingdom S Clayton
United Kingdom J O'Mara
6 6
3 Italy A Bega
Austria L Miedler
3 79 [10] France D Guez
Belgium Y Mertens
3 2
WC United Kingdom J Fearnley
United Kingdom C Thomson
6 67 [6] 3 Italy A Bega
Austria L Miedler
65 6 [5]
Czech Republic Marek Jaloviec
Spain B Zapata Miralles
1 1 France D Guez
Belgium Y Mertens
77 1 [10]
France D Guez
Belgium Y Mertens
6 6 1 United Kingdom S Clayton
United Kingdom J O'Mara
1 5
Serbia N Milojević
Italy L Vanni
3 6 [10] Spain G Granollers
Spain G Olaso
6 7
Alt Germany D Brands
Germany R Kern
6 3 [4] Serbia N Milojević
Italy L Vanni
3 62
WC United Kingdom Reuben Henry
United Kingdom Scott MacAulay
2 2 4 Finland H Heliövaara
Russia E Karlovskiy
6 77
4 Finland H Heliövaara
Russia E Karlovskiy
6 6 4 Finland H Heliövaara
Russia E Karlovskiy
3 4
United States JC Aragone
United States Jared Hiltzik
4 6 [5] Spain G Granollers
Spain G Olaso
6 6
WC United Kingdom S Duncan
United Kingdom Kieran MacArty
6 2 [10] WC United Kingdom S Duncan
United Kingdom K MacArty
5 4
Spain G Granollers
Spain G Olaso
7 6 Spain G Granollers
Spain G Olaso
7 6
2 Spain R Ortega Olmedo
Spain M Vilella Martínez
5 3
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References

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