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2018 Milex Open – Doubles
2018 tennis event results From Wikipedia, the free encyclopedia
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Juan Ignacio Londero and Luis David Martínez were the defending champions but only Londero chose to defend his title, partnering Tomás Lipovšek Puches. Londero lost in the semifinals to Leander Paes and Miguel Ángel Reyes-Varela.
Paes and Reyes-Varela won the title after defeating Ariel Behar and Roberto Quiroz 4–6, 6–3, [10–5] in the final.
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Seeds
Pablo Cuevas /
David Marrero (quarterfinals)
Leander Paes /
Miguel Ángel Reyes-Varela (champions)
Marcelo Arévalo /
Jeevan Nedunchezhiyan (quarterfinals)
Gonzalo Escobar /
Fernando Romboli (quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 6 | |||||||||||||||||||||||||
3 | 3 | 1 | 3 | 7 | [7] | ||||||||||||||||||||||
WC | 0 | 3 | WC | 6 | 5 | [10] | |||||||||||||||||||||
WC | 6 | 6 | WC | 3 | 6 | [3] | |||||||||||||||||||||
3 | 6 | 77 | 6 | 3 | [10] | ||||||||||||||||||||||
WC | 3 | 62 | 3 | 7 | 4 | [7] | |||||||||||||||||||||
2 | 6 | [5] | 5 | 6 | [10] | ||||||||||||||||||||||
6 | 4 | [10] | 6 | 3 | [5] | ||||||||||||||||||||||
w/o | 2 | 4 | 6 | [10] | |||||||||||||||||||||||
65 | 78 | [11] | |||||||||||||||||||||||||
64 | 62 | 4 | 77 | 66 | [9] | ||||||||||||||||||||||
4 | 77 | 77 | 4 | 63 | |||||||||||||||||||||||
6 | 6 | 2 | 6 | 77 | |||||||||||||||||||||||
3 | 3 | 5 | 67 | ||||||||||||||||||||||||
3 | 0 | 2 | 7 | 79 | |||||||||||||||||||||||
2 | 6 | 6 |
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References
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