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2018 Silicon Valley Classic – Doubles
2018 tennis event results From Wikipedia, the free encyclopedia
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Abigail Spears and CoCo Vandeweghe were the defending champions, but chose not to participate this year.
Latisha Chan and Květa Peschke won the title, defeating Lyudmyla and Nadiia Kichenok in the final, 6–4, 6–1.
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Seeds
Latisha Chan /
Květa Peschke (champions)
Mihaela Buzărnescu /
Heather Watson (semifinals)
Lyudmyla Kichenok /
Nadiia Kichenok (final)
Miyu Kato /
Makoto Ninomiya (semifinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | w/o | |||||||||||||||||||||||||
![]() ![]() | 4 | 1 | ![]() ![]() | ||||||||||||||||||||||||
![]() ![]() | 6 | 6 | 1 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
4 | ![]() ![]() | 1 | 7 | [10] | 4 | ![]() ![]() | 1 | 4 | |||||||||||||||||||
![]() ![]() | 6 | 5 | [4] | 4 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||
![]() ![]() | 4 | 4 | ![]() ![]() | 4 | 2 | ||||||||||||||||||||||
![]() ![]() | 6 | 6 | 1 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 3 | 3 | 3 | ![]() ![]() | 4 | 1 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 6 | 2 | [6] | |||||||||||||||||||||
![]() ![]() | 6 | 3 | [7] | 3 | ![]() ![]() | 1 | 6 | [10] | |||||||||||||||||||
3 | ![]() ![]() | 4 | 6 | [10] | 3 | ![]() ![]() | 6 | 3 | [10] | ||||||||||||||||||
![]() ![]() | 3 | 2 | 2 | ![]() ![]() | 4 | 6 | [8] | ||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 5 | 2 | ||||||||||||||||||||||
WC | ![]() ![]() | 3 | 3 | 2 | ![]() ![]() | 7 | 6 | ||||||||||||||||||||
2 | ![]() ![]() | 6 | 6 |
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External links
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