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2019 Arizona Tennis Classic – Doubles
2019 tennis event results From Wikipedia, the free encyclopedia
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This was the first edition of the tournament.
Jamie Murray and Neal Skupski won the title after defeating Austin Krajicek and Artem Sitak 6–7(2–7), 7–5, [10–6] in the final.
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Seeds
Jamie Murray /
Neal Skupski (champions)
Austin Krajicek /
Artem Sitak (final)
Rohan Bopanna /
Divij Sharan (quarterfinals)
Marcelo Demoliner /
Frederik Nielsen (quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 77 | ||||||||||||||||||||||||
WC | ![]() ![]() | 3 | 64 | 1 | ![]() ![]() | 68 | 6 | [12] | |||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 710 | 4 | [10] | |||||||||||||||||||||
![]() ![]() | 4 | 2 | 1 | ![]() ![]() | 65 | 6 | [11] | ||||||||||||||||||||
4 | ![]() ![]() | 6 | 6 | WC | ![]() ![]() | 77 | 0 | [9] | |||||||||||||||||||
![]() ![]() | 2 | 4 | 4 | ![]() ![]() | 6 | 4 | [8] | ||||||||||||||||||||
![]() ![]() | WC | ![]() ![]() | 3 | 6 | [10] | ||||||||||||||||||||||
WC | ![]() ![]() | w/o | 1 | ![]() ![]() | 62 | 7 | [10] | ||||||||||||||||||||
![]() ![]() | 6 | 7 | 2 | ![]() ![]() | 77 | 5 | [6] | ||||||||||||||||||||
WC | ![]() ![]() | 1 | 5 | ![]() ![]() | 63 | 79 | [12] | ||||||||||||||||||||
![]() ![]() | 3 | 4 | 3 | ![]() ![]() | 77 | 67 | [10] | ||||||||||||||||||||
3 | ![]() ![]() | 6 | 6 | ![]() ![]() | 6 | 4 | [7] | ||||||||||||||||||||
![]() ![]() | 3 | 2 | 2 | ![]() ![]() | 4 | 6 | [10] | ||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | ||||||||||||||||||||||||
2 | ![]() ![]() | w/o |
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External links
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