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2019 Arizona Tennis Classic – Doubles

2019 tennis event results From Wikipedia, the free encyclopedia

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This was the first edition of the tournament.

Quick facts Doubles, Final ...

Jamie Murray and Neal Skupski won the title after defeating Austin Krajicek and Artem Sitak 6–7(2–7), 7–5, [10–6] in the final.

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Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 United Kingdom J Murray
United Kingdom N Skupski
6 77
WC Chinese Taipei J Jung
United States M Krueger
3 64 1 United Kingdom J Murray
United Kingdom N Skupski
68 6 [12]
New Zealand M Daniell
Netherlands W Koolhof
6 6 New Zealand M Daniell
Netherlands W Koolhof
710 4 [10]
Mexico S González
Pakistan A-u-H Qureshi
4 2 1 United Kingdom J Murray
United Kingdom N Skupski
65 6 [11]
4 Brazil M Demoliner
Denmark F Nielsen
6 6 WC Italy A Arnaboldi
Italy S Caruso
77 0 [9]
Israel J Erlich
France F Martin
2 4 4 Brazil M Demoliner
Denmark F Nielsen
6 4 [8]
Australia M Ebden
United States R Harrison
WC Italy A Arnaboldi
Italy S Caruso
3 6 [10]
WC Italy A Arnaboldi
Italy S Caruso
w/o 1 United Kingdom J Murray
United Kingdom N Skupski
62 7 [10]
United States J Cerretani
United States N Monroe
6 7 2 United States A Krajicek
New Zealand A Sitak
77 5 [6]
WC Serbia P Krstin
Serbia N Zimonjić
1 5 United States J Cerretani
United States N Monroe
63 79 [12]
Belgium R Bemelmans
Canada P Polansky
3 4 3 India R Bopanna
India D Sharan
77 67 [10]
3 India R Bopanna
India D Sharan
6 6 United States J Cerretani
United States N Monroe
6 4 [7]
United States R Galloway
United States N Lammons
3 2 2 United States A Krajicek
New Zealand A Sitak
4 6 [10]
Argentina G Andreozzi
Chile N Jarry
6 6 Argentina G Andreozzi
Chile N Jarry
2 United States A Krajicek
New Zealand A Sitak
w/o
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