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2019 Córdoba Open – Doubles

2019 tennis event results From Wikipedia, the free encyclopedia

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This was the first edition of the tournament.[1]

Quick Facts Doubles, Final ...

Roman Jebavý and Andrés Molteni won the title, defeating Máximo González and Horacio Zeballos in the final, 6–4, 7–6(7–4).

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Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Argentina M González
Argentina H Zeballos
6 6
Argentina G Andreozzi
Argentina L Mayer
1 1 1 Argentina M González
Argentina H Zeballos
w/o
Spain P Carreño Busta
Spain G Granollers
77 65 [10] Spain P Carreño Busta
Spain G Granollers
Spain D Marrero
Spain J Munar
64 77 [8] 1 Argentina M González
Argentina H Zeballos
4 77 [10]
4 El Salvador M Arévalo
United States J Cerretani
5 65 Belgium S Gillé
Belgium J Vliegen
6 63 [5]
Belgium S Gillé
Belgium J Vliegen
7 77 Belgium S Gillé
Belgium J Vliegen
6 4 [10]
Spain R Carballés Baena
Tunisia M Jaziri
78 2 [8] WC Argentina F Argüello
Argentina P Cachin
4 6 [4]
WC Argentina F Argüello
Argentina P Cachin
66 6 [10] 1 Argentina M González
Argentina H Zeballos
4 64
United States N Monroe
Mexico MÁ Reyes-Varela
77 6 3 Czech Republic R Jebavý
Argentina A Molteni
6 77
Uruguay P Cuevas
Argentina D Schwartzman
64 4 United States N Monroe
Mexico MÁ Reyes-Varela
3 64
Chile N Jarry
Italy P Lorenzi
3 4 3 Czech Republic R Jebavý
Argentina A Molteni
6 77
3 Czech Republic R Jebavý
Argentina A Molteni
6 6 3 Czech Republic R Jebavý
Argentina A Molteni
6 6
Slovenia A Bedene
Germany M Marterer
4 6 [10] WC Argentina F Bagnis
Argentina G Durán
4 4
Argentina G Pella
Chile H Podlipnik Castillo
6 1 [5] Slovenia A Bedene
Germany M Marterer
3 3
WC Argentina F Bagnis
Argentina G Durán
6 6 WC Argentina F Bagnis
Argentina G Durán
6 6
2 Brazil M Demoliner
Denmark F Nielsen
3 4
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References

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