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2019 Hungarian Open – Doubles

2019 tennis event results From Wikipedia, the free encyclopedia

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Dominic Inglot and Franko Škugor were the defending champions,[1] but Škugor chose to compete in Barcelona instead. Inglot played alongside Rohan Bopanna, but lost in the quarterfinals to Andre Begemann and Ernests Gulbis.

Quick Facts Doubles, Final ...

Ken and Neal Skupski won the title, defeating Marcus Daniell and Wesley Koolhof in the final, 6–3, 6–4.

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Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 India R Bopanna
United Kingdom D Inglot
6 7
Alt Italy T Fabbiano
Australia J Millman
3 5 1 India R Bopanna
United Kingdom D Inglot
3 4
Alt Germany A Begemann
Latvia E Gulbis
6 7 Alt Germany A Begemann
Latvia E Gulbis
6 6
Czech Republic R Jebavý
Argentina A Molteni
4 5 Alt Germany A Begemann
Latvia E Gulbis
2 77 [6]
3 United Kingdom K Skupski
United Kingdom N Skupski
6 77 3 United Kingdom K Skupski
United Kingdom N Skupski
6 62 [10]
WC Hungary M Valkusz
Serbia N Zimonjić
0 64 3 United Kingdom K Skupski
United Kingdom N Skupski
78 5 [10]
Sweden R Lindstedt
Pakistan A-u-H Qureshi
3 6 [9] Brazil M Demoliner
India D Sharan
66 7 [7]
Brazil M Demoliner
India D Sharan
6 4 [11] 3 United Kingdom K Skupski
United Kingdom N Skupski
6 6
New Zealand M Daniell
Netherlands W Koolhof
6 6 New Zealand M Daniell
Netherlands W Koolhof
3 4
Poland H Hurkacz
France F Martin
2 3 New Zealand M Daniell
Netherlands W Koolhof
6 77
WC Hungary G Borsos
Hungary P Nagy
6 3 [8] 4 Netherlands R Haase
Denmark F Nielsen
4 65
4 Netherlands R Haase
Denmark F Nielsen
2 6 [10] New Zealand M Daniell
Netherlands W Koolhof
3 6 [10]
Moldova R Albot
Georgia (country) N Basilashvili
3 3 Germany K Krawietz
Germany A Mies
6 2 [8]
Germany K Krawietz
Germany A Mies
6 6 Germany K Krawietz
Germany A Mies
3 6 [10]
United Kingdom L Bambridge
United Kingdom J O'Mara
3 6 [10] United Kingdom L Bambridge
United Kingdom J O'Mara
6 4 [6]
2 Mexico S González
Netherlands M Middelkoop
6 3 [8]
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References

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