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2019 Jacksonville mayoral election

From Wikipedia, the free encyclopedia

2019 Jacksonville mayoral election
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The 2019 Jacksonville mayoral election was held on March 19, 2019, to elect the mayor of Jacksonville. Incumbent mayor Lenny Curry, a Republican, won a majority of votes to win a second term in office.[2] No Democratic candidate qualified for the mayoral election.[3]

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Candidates

Republican Party

Declared

Democratic Party

While Democratic candidates did declare their candidacy, no Democratic candidates qualified for the mayoral election in 2019.

Declared

  • Doreszell Cohen, founder of Citizens for Criminal Justice Reform[7]
  • Yolanda Thornton, small business owner[8]

Declined

Independents

Declared

  • Omega Allen, Chair of the NW Jacksonville Economic Development Trust Fund
  • Connell Crooms, nonprofit director[11]
  • Vishaun Grissett, independent consultant[12]
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Campaign and results

Democrats did not field a candidate for Mayor of Jacksonville in the 2019 election. Curry faced Anna Lopez Brosche, described by The Florida Times-Union as a moderate Republican. Brosche's campaign received support from some Democratic politicians, including city councilman Garrett Dennis and former Duval County Democratic Party chair Lisa King.[3]

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References

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