2019 Kiskút Open – Doubles

This was the first edition of the tournament.^[1]

Doubles
2019 Kiskút Open
Champions	Irina Bara Maryna Zanevska
Runners-up	Akgul Amanmuradova Elena Bogdan
Score	3–6, 6–2, [10–8]

Main article: 2019 Kiskút Open

Irina Bara and Maryna Zanevska won the title, defeating Akgul Amanmuradova and Elena Bogdan in the final, 3–6, 6–2, [10–8].

Seeds

1. Georgina García Pérez / Fanny Stollár (first round, retired)
2. Amina Anshba / Anastasia Dețiuc (semifinals)
3. Nicoleta Dascălu / Danka Kovinić (semifinals)
4. Akgul Amanmuradova / Elena Bogdan (final)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• Alt = Alternate
• ITF = ITF entry
• PR = Protected ranking
• SR = Special ranking
• SE = Special exempt
• JE = Junior exempt
• JR = Junior Accelerator Programme entrant
• CO = College Accelerator Programme entrant
• NG = Next Gen Accelerator Program entrant
• w/o = Walkover
• r = Retired
• d = Defaulted

Draw

	First round							Quarterfinals							Semifinals							Final
	1	G García Pérez F Stollár	3	0r
		I Bara M Zanevska	6	1					I Bara M Zanevska	6	6
		RL Jani P Ormaechea	5	6	[10]				RL Jani P Ormaechea	2	3
		M Chwalińska A Nagy	7	3	[7]											I Bara M Zanevska	77	6
	3	N Dascălu D Kovinić	w/o												3	N Dascălu D Kovinić	63	1
		V Juhászová M Klaffner						3	N Dascălu D Kovinić	6	6
		A Bondár R Šramková	0	6	[10]				A Bondár R Šramková	4	2
		G Cé S Waltert	6	4	[8]																		I Bara M Zanevska	3	6	[10]
		M Chernyshova C Škamlová	w/o																			4	A Amanmuradova E Bogdan	6	2	[8]
	WC	Á Bukta T Pereira							M Chernyshova C Škamlová	2	64
	WC	B Békefi D Drahota-Szabó	3	4				4	A Amanmuradova E Bogdan	6	77
	4	A Amanmuradova E Bogdan	6	6											4	A Amanmuradova E Bogdan	2	6	[10]
		M Bulgaru IG Ghioroaie	6	6											2	A Anshba A Dețiuc	6	4	[4]
		J Marková D Seguel	4	2					M Bulgaru IG Ghioroaie	2	3
		N Potočnik N Radišič	4	3				2	A Anshba A Dețiuc	6	6
	2	A Anshba A Dețiuc	6	6