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2019 Kiskút Open II – Doubles

2019 tennis event results From Wikipedia, the free encyclopedia

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This was the first edition of the tournament.[1]

Quick facts Doubles, Final ...

Georgina García Pérez and Fanny Stollár won the title, defeating Nina Potočnik and Nika Radišič in the final, 6–1, 7–6(7–4).

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Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Japan M Ninomiya
Czech Republic R Voráčová
6 4 [10]
  Romania M Bulgaru
Romania I Fetecău
4 6 [6] 1 Japan M Ninomiya
Czech Republic R Voráčová
6 4 [3]
  Hungary A Bondár
Hungary D Gálfi
6 7 Hungary A Bondár
Hungary D Gálfi
4 6 [10]
  Russia A Fomina
Slovakia V Juhászová
1 5 Hungary A Bondár
Hungary D Gálfi
4 3
3 Romania I Bara
Hungary RL Jani
6 6 Slovenia N Potočnik
Slovenia N Radišič
6 6
  Uzbekistan A Amanmuradova
Romania E Bogdan
2 3 3 Romania I Bara
Hungary RL Jani
  Poland M Chwalińska
Italy E Cocciaretto
4 4 Slovenia N Potočnik
Slovenia N Radišič
w/o
  Slovenia N Potočnik
Slovenia N Radišič
6 6 Slovenia N Potočnik
Slovenia N Radišič
1 64
  Belgium M Benoît
Romania A Cadanțu
3 77 [6] 2 Spain G García Pérez
Hungary F Stollár
6 77
  Russia A Anshba
Czech Republic A Dețiuc
6 64 [10] Russia A Anshba
Czech Republic A Dețiuc
7 66 [5]
  Ukraine M Chernyshova
Slovakia C Škamlová
6 6 Ukraine M Chernyshova
Slovakia C Škamlová
5 78 [10]
4 Italy G Marchetti
Bulgaria I Shinikova
2 1 Ukraine M Chernyshova
Slovakia C Škamlová
2 1
WC Hungary B Békefi
Hungary D Drahota-Szabó
2 1 2 Spain G García Pérez
Hungary F Stollár
6 6
  Austria B Haas
Slovakia R Šramková
6 6 Austria B Haas
Slovakia R Šramková
WC Hungary G Arn
Hungary A Nagy
3 2 2 Spain G García Pérez
Hungary F Stollár
w/o
2 Spain G García Pérez
Hungary F Stollár
6 6
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References

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