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2019 Lale Cup – Doubles

2019 tennis event results From Wikipedia, the free encyclopedia

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Ayla Aksu and Harriet Dart were the defending champions, but both players chose not to participate.

Quick Facts Doubles, Final ...

Marie Bouzková and Rosalie van der Hoek won the title, defeating Ilona Kremen and Iryna Shymanovich in the final, 7–5, 6–7(2–7), [10–5].[1]

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Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Russia O Doroshina
Russia P Monova
  Turkey Ç Büyükakçay
Croatia A Vrljić
w/o Turkey Ç Büyükakçay
Croatia A Vrljić
  Ukraine G Poznikhirenko
Uzbekistan S Sharipova
7 4 [8] Czech Republic M Bouzková
Netherlands R van der Hoek
w/o
  Czech Republic M Bouzková
Netherlands R van der Hoek
5 6 [10] Czech Republic M Bouzková
Netherlands R van der Hoek
7 7
3 Turkey B Cengiz
Indonesia J Rompies
6 6 3 Turkey B Cengiz
Indonesia J Rompies
5 5
WC Turkey Z Erman
Turkey Z Sönmez
3 4 3 Turkey B Cengiz
Indonesia J Rompies
1 6 [11]
  Turkey İ Soylu
Czech Republic B Štefková
6 6 Turkey İ Soylu
Czech Republic B Štefková
6 4 [9]
WC Turkey İ Öz
Turkey M Sezer
3 3 Czech Republic M Bouzková
Netherlands R van der Hoek
7 62 [10]
  Belarus I Kremen
Belarus I Shymanovich
6 6 Belarus I Kremen
Belarus I Shymanovich
5 77 [5]
  Hungary Á Bukta
Slovakia V Juhászová
2 3 Belarus I Kremen
Belarus I Shymanovich
4 6 [11]
  Belgium G Minnen
Turkey P Özgen
7 6 Belgium G Minnen
Turkey P Özgen
6 3 [9]
4 Greece V Grammatikopoulou
India A Raina
5 4 Belarus I Kremen
Belarus I Shymanovich
66 6 [11]
  Russia A Gasanova
Bulgaria J Terziyska
6 77 2 Cyprus R Șerban
Bulgaria I Shinikova
78 3 [9]
  Oman F Al-Nabhani
Turkey C Anıl
1 63 Russia A Gasanova
Bulgaria J Terziyska
6 62 [7]
WC Switzerland L Aiche
Turkey BE Gümüşsoy
0 0 2 Cyprus R Șerban
Bulgaria I Shinikova
4 77 [10]
2 Cyprus R Șerban
Bulgaria I Shinikova
6 6
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References

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