2019 Montgomery mayoral election

The 2019 Montgomery mayoral election took place on August 28 and October 8, 2019, to elect the Mayor of Montgomery, Alabama.

2019 Montgomery mayoral election

← 2015 August 28, 2019 (first round) October 8, 2019 (second round) 2023 →

Candidate Steven Reed David Woods Party Nonpartisan Nonpartisan First round 18,571 42.49% 10,272 23.50% Second round 32,918 67.28% 16,010 32.72%   Candidate Ed Crowell J. C. Love III Party Nonpartisan Nonpartisan First round 5,272 12.06% 4,251 9.73%

Mayor before election Todd Strange Republican Elected mayor Steven Reed Democratic

Incumbent Republican Mayor Todd Strange, who had been elected to a partial term and two full terms as mayor, did not seek re-election to a fourth full term in office.

The election was officially nonpartisan.

With no candidate receiving a majority of the vote, a runoff election was held between the top two candidates. Two candidates, Montgomery County Probate Judge Steven Reed and businessman David Woods, made it to the October 8 runoff, with Reed winning the runoff.

Reed then became the city's first African-American mayor after being sworn in on November 12, 2019.^[1][2]

Results

First round

First round results^[3]

Party		Candidate	Votes	%
	Nonpartisan	Steven Reed	18,571	42.49
	Nonpartisan	David Woods	10,272	23.50
	Nonpartisan	Ed Crowell	5,272	12.06
	Nonpartisan	J. C. Love III	4,251	9.73
	Nonpartisan	Elton Norris Dean Sr.	1,835	4.20
	Nonpartisan	Artur Davis	1,784	4.08
	Nonpartisan	Victorrus Felder	879	2.01
	Nonpartisan	Shannon Ferrari	289	0.64
	Nonpartisan	Ronald L. Davis	186	0.43
	Nonpartisan	Bibby Simmons	156	0.36
	Nonpartisan	Butler Browder	127	0.29
	Nonpartisan	Hobson Cox	92	0.21

Second round

Runoff results^[4]

Party		Candidate	Votes	%
	Nonpartisan	Steven Reed	32,918	67.2
	Nonpartisan	David Woods	16,010	32.7