Montmahoux

Montmahoux (French pronunciation: [mɔ̃ma.u]) is a commune in the Doubs department in the Bourgogne-Franche-Comté region in eastern France.

Montmahoux
Commune
An aerial view of Montmahoux
Coat of arms
Location of Montmahoux
Montmahoux Show map of France Montmahoux Show map of Bourgogne-Franche-Comté
Coordinates: 46°59′03″N 6°02′06″E
Country	France
Region	Bourgogne-Franche-Comté
Department	Doubs
Arrondissement	Besançon
Canton	Ornans
Intercommunality	Loue-Lison
Government
• Mayor (2020–2026)	Vincent Marguet[1]
Area 1	6.52 km2 (2.52 sq mi)
Population  (2022)[2]	91
• Density	14/km2 (36/sq mi)
Time zone	UTC+01:00 (CET)
• Summer (DST)	UTC+02:00 (CEST)
INSEE/Postal code	25404 /25270
Elevation	550–823 m (1,804–2,700 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Geography

Montmahoux lies 8 km (5.0 mi) south of Amancey on the edge of the gorge of the Boz.

Population

Historical population

Year	Pop.	±%
1962	90	—
1968	106	+17.8%
1975	95	−10.4%
1982	76	−20.0%
1990	80	+5.3%
1999	67	−16.2%
2008	80	+19.4%
2012	105	+31.2%

See also

• Communes of the Doubs department