$\begin{array}{l}

x+2 y+z=4 \\

2 x+y+2 z=5 \\

x-y+z=1

\end{array}$ The system of algebraic equations given above has

(A) a unique solution of $x=1, y=1$ and $z=1$.

(B) only the two solutions of $(x=1, y=1, z=1)$ and $(x=2, y=1, z=0)$.

(C) infinite number of solutions.

(D) no feasible solution.

$\begin{array}{l}

x+2 y+z=4 \\

2 x+y+2 z=5 \\

x-y+z=1

\end{array}$ The system of algebraic equations given above has

(A) a unique solution of $x=1, y=1$ and $z=1$.

(B) only the two solutions of $(x=1, y=1, z=1)$ and $(x=2, y=1, z=0)$.

(C) infinite number of solutions.

(D) no feasible solution.

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