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Samarium(III) bromide
Chemical compound From Wikipedia, the free encyclopedia
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Samarium(III) bromide is a crystalline compound of one samarium and three bromine atoms with the chemical formula of SmBr3. The compound has a crystal structure isotypic to that of plutonium(III) bromide.[4][5]
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Preparation
SmBr3·6H2O can be crystallized by dissolving samarium oxide in 40% hydrobromic acid. The hydrate and ammonium bromide are heated in a vacuum to obtain the anhydrous form of samarium(III) bromide.[2]
Other compounds
Samarium(III) bromide forms some compounds with hydrazine, such as SmBr3·3N2H4·H2O which is a pale yellow needle-shaped crystal that is soluble in water and ethanol but insoluble in benzene, with d20 °C = 3.147 g/cm3.[6]
References
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